JPSC Recruitment AE 2019
Jharkhand Public Service Commission (JPSC) Recruitment of Combined Assistant Engineer (Regular), Advt. No. 05/2019
Post Name-Assistant Engineer (AE)
Total Post-637
AE Civil-542
AE Mechanical-95
Educational Qualification-Degree in Civil/Mechanical engineering
Age Limit-21 To 35 Years on 01/08/2019
Pay Scale-Rs 9300-34800 Grade Pay 54000
Application Fee-Rs 600 UR/OBC Rs.150 SC/ST/EWS
Selection Process-Based on objective General ability test, Paper I & Paper II written exam and Main examination followed by interview.
JPSC Recruitment AE 2019
Exam Pattern-Written Mark-1000,Interview Marks-200
Pre Exam-General ability test/Paper I/Paper II
Total Marks-200
Total Time-2 Hours
Negative Marking-0.25
Main Exam-Paper I/Paper II
Total Marks-200
Total Time-3 Hours
Negative Marking-0.25
Category: New Jobs
Important Date-
Online Application Start-15/10/2019
Online Application Closed-11/11/2019
Last Date Deposit Fee-13/11/2019
Click Here For Full Notification
Click Here For Online Application And More Details
