# ONLINE MCQ EE-TRANSMISSION AND DISTRIBUTION 3

Q21. Which of the following equipment is
used to limit short-circuit current level
in a substation ?
A.  Isolator
B.  Lightning switch
C.  Coupling capacitor
D.  Series reactor
 \$(document).ready(function(){ \$(‘#loaddata4116’).click(function(){ qid4116=\$(‘#qid4116’).val(); section4116=\$(‘#section4116’).val(); type4116=\$(‘#type4116’).val(); subtype4116=\$(‘#subtype4116’).val(); \$.post(‘../../fav’,{ qid:qid4116, section: section4116, type: type4116, subtype: subtype4116 },function(ajaxresult){ \$(‘#getrequest4116’).html(ajaxresult); qid4116=\$(‘#qid4116’).val(”); section4116=\$(‘#section4116’).val(”); type4116=\$(‘#type4116’).val(”); subtype4116=\$(‘#subtype4116’).val(”); }); }); }); Explanation:- Answer : D

Q22. For exact compensation of voltage drop
in the feeder the booster
A.  must be earthed
B.  must work on line voltage
C.  must work on linear portion of its
V-I characteristics
D.  must work on non-linear portion of
its V-I characteFistics
 \$(document).ready(function(){ \$(‘#loaddata4117’).click(function(){ qid4117=\$(‘#qid4117’).val(); section4117=\$(‘#section4117’).val(); type4117=\$(‘#type4117’).val(); subtype4117=\$(‘#subtype4117’).val(); \$.post(‘../../fav’,{ qid:qid4117, section: section4117, type: type4117, subtype: subtype4117 },function(ajaxresult){ \$(‘#getrequest4117’).html(ajaxresult); qid4117=\$(‘#qid4117’).val(”); section4117=\$(‘#section4117’).val(”); type4117=\$(‘#type4117’).val(”); subtype4117=\$(‘#subtype4117’).val(”); }); }); }); Explanation:- Answer : C

Q23. System grounding is done so that
A.  inductive interference between power
and communication circuits can be
controlled
B.  the floating potential on the lower
voltage winding for a transformer is
brought down to an insignificant
value
C.  the arcing faults to earth would not
set up dangerously high voltage on
healthy phases
D.  for all above reasons
 \$(document).ready(function(){ \$(‘#loaddata4118’).click(function(){ qid4118=\$(‘#qid4118’).val(); section4118=\$(‘#section4118’).val(); type4118=\$(‘#type4118’).val(); subtype4118=\$(‘#subtype4118’).val(); \$.post(‘../../fav’,{ qid:qid4118, section: section4118, type: type4118, subtype: subtype4118 },function(ajaxresult){ \$(‘#getrequest4118’).html(ajaxresult); qid4118=\$(‘#qid4118’).val(”); section4118=\$(‘#section4118’).val(”); type4118=\$(‘#type4118’).val(”); subtype4118=\$(‘#subtype4118’).val(”); }); }); }); Explanation:- Answer : D

Q24. The effective resistance of a conductor
will be the same as ‘ohmic resistance’
when
A.  power factor is unity
B.  current is uniformly distributed in
the conductor cross-section
C.  voltage is low
D.  current is in true sine wave form
 \$(document).ready(function(){ \$(‘#loaddata4119’).click(function(){ qid4119=\$(‘#qid4119’).val(); section4119=\$(‘#section4119’).val(); type4119=\$(‘#type4119’).val(); subtype4119=\$(‘#subtype4119’).val(); \$.post(‘../../fav’,{ qid:qid4119, section: section4119, type: type4119, subtype: subtype4119 },function(ajaxresult){ \$(‘#getrequest4119’).html(ajaxresult); qid4119=\$(‘#qid4119’).val(”); section4119=\$(‘#section4119’).val(”); type4119=\$(‘#type4119’).val(”); subtype4119=\$(‘#subtype4119’).val(”); }); }); }); Explanation:- Answer : B

Q25. The surge resistance of cables is
A.  20 ohms
B.  50 ohms
C.  200 ohms
D.  300 ohms
 \$(document).ready(function(){ \$(‘#loaddata4120’).click(function(){ qid4120=\$(‘#qid4120’).val(); section4120=\$(‘#section4120’).val(); type4120=\$(‘#type4120’).val(); subtype4120=\$(‘#subtype4120’).val(); \$.post(‘../../fav’,{ qid:qid4120, section: section4120, type: type4120, subtype: subtype4120 },function(ajaxresult){ \$(‘#getrequest4120’).html(ajaxresult); qid4120=\$(‘#qid4120’).val(”); section4120=\$(‘#section4120’).val(”); type4120=\$(‘#type4120’).val(”); subtype4120=\$(‘#subtype4120’).val(”); }); }); }); Explanation:- Answer : B

Q26. In the cables sheaths are used to
A.  prevent the moisture from entering
the cable
B.  provide strength to the cable
C.  provide proper insulation
D.  none of the above
 \$(document).ready(function(){ \$(‘#loaddata4121’).click(function(){ qid4121=\$(‘#qid4121’).val(); section4121=\$(‘#section4121’).val(); type4121=\$(‘#type4121’).val(); subtype4121=\$(‘#subtype4121’).val(); \$.post(‘../../fav’,{ qid:qid4121, section: section4121, type: type4121, subtype: subtype4121 },function(ajaxresult){ \$(‘#getrequest4121’).html(ajaxresult); qid4121=\$(‘#qid4121’).val(”); section4121=\$(‘#section4121’).val(”); type4121=\$(‘#type4121’).val(”); subtype4121=\$(‘#subtype4121’).val(”); }); }); }); Explanation:- Answer : A

Q27. Which of the following are the constants
of the transmission lines ?
A.  Resistance
B.  Inductance
C.  Capacitance
D.  All of the above
 \$(document).ready(function(){ \$(‘#loaddata3934’).click(function(){ qid3934=\$(‘#qid3934’).val(); section3934=\$(‘#section3934’).val(); type3934=\$(‘#type3934’).val(); subtype3934=\$(‘#subtype3934’).val(); \$.post(‘../../fav’,{ qid:qid3934, section: section3934, type: type3934, subtype: subtype3934 },function(ajaxresult){ \$(‘#getrequest3934’).html(ajaxresult); qid3934=\$(‘#qid3934’).val(”); section3934=\$(‘#section3934’).val(”); type3934=\$(‘#type3934’).val(”); subtype3934=\$(‘#subtype3934’).val(”); }); }); }); Explanation:- Answer : D

Q28. Which of the following methods is used
for laying of underground cables ?
A.  Direct laying
B.  Draw-in-system
C.  Solid system
D.  All of the above
 \$(document).ready(function(){ \$(‘#loaddata3935’).click(function(){ qid3935=\$(‘#qid3935’).val(); section3935=\$(‘#section3935’).val(); type3935=\$(‘#type3935’).val(); subtype3935=\$(‘#subtype3935’).val(); \$.post(‘../../fav’,{ qid:qid3935, section: section3935, type: type3935, subtype: subtype3935 },function(ajaxresult){ \$(‘#getrequest3935’).html(ajaxresult); qid3935=\$(‘#qid3935’).val(”); section3935=\$(‘#section3935’).val(”); type3935=\$(‘#type3935’).val(”); subtype3935=\$(‘#subtype3935’).val(”); }); }); }); Explanation:- Answer : D

Q29. Most of the high voltage transmission
lines in India are
A.  undergound
C.  either of the above
D.  none of the above
 \$(document).ready(function(){ \$(‘#loaddata3936’).click(function(){ qid3936=\$(‘#qid3936’).val(); section3936=\$(‘#section3936’).val(); type3936=\$(‘#type3936’).val(); subtype3936=\$(‘#subtype3936’).val(); \$.post(‘../../fav’,{ qid:qid3936, section: section3936, type: type3936, subtype: subtype3936 },function(ajaxresult){ \$(‘#getrequest3936’).html(ajaxresult); qid3936=\$(‘#qid3936’).val(”); section3936=\$(‘#section3936’).val(”); type3936=\$(‘#type3936’).val(”); subtype3936=\$(‘#subtype3936’).val(”); }); }); }); Explanation:- Answer : B