1).Find the difference between the 30th
and the 34th term of the series 16, 32, 48, 64….
and the 34th term of the series 16, 32, 48, 64….
a)
72
72
b)
66
66
c)
68
68
d)
64
64
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2).The LCM of two numbers is 55 times their
HCF. The sum of the LCM and the HCF is 6272. If one number is 280, then the
other number is
HCF. The sum of the LCM and the HCF is 6272. If one number is 280, then the
other number is
a)
2464
2464
b)
3226
3226
c)
6272
6272
d)
2326
2326
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3).The total earning of A, B and C is Rs 95000
and they save 30%, 25% and 20% of their incomes respectively. If savings are in
the ratio of 4: 5: 6, then what is the difference between the amount of
earnings of B and C?
and they save 30%, 25% and 20% of their incomes respectively. If savings are in
the ratio of 4: 5: 6, then what is the difference between the amount of
earnings of B and C?
a)
Rs. 21000
Rs. 21000
b)
Rs. 9000
Rs. 9000
c)
Rs. 18000
Rs. 18000
d)
Rs. 15000
Rs. 15000
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4).The numbers of boys and girls in a college
are in the ration of 4: 1. If 50% of the boys and 75% of the girls are adults,
the percentage of students who are not adults is?
are in the ration of 4: 1. If 50% of the boys and 75% of the girls are adults,
the percentage of students who are not adults is?
a)
40%
40%
b)
45%
45%
c)
30%
30%
d)
50%
50%
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5).A trader sells his goods at 20% profit. Had
he bought it at 10% more and sold it for Rs. 70 more, he would have gained 25%.
Find the cost price of the goods.
he bought it at 10% more and sold it for Rs. 70 more, he would have gained 25%.
Find the cost price of the goods.
a)
Rs. 800
Rs. 800
b)
Rs. 200
Rs. 200
c)
Rs. 400
Rs. 400
d)
Rs. 600
Rs. 600
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6).The difference between a discount of 40% on
Rs. 1000 and two successive discount of 36% and 5% on the same amount is:
Rs. 1000 and two successive discount of 36% and 5% on the same amount is:
a)
Rs. 8
Rs. 8
b)
Rs. 4
Rs. 4
c)
Rs. 16
Rs. 16
d)
Rs. 24
Rs. 24
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7).At the certain rate of simple interest a
sum becomes double in 14 years. In how many years will it become 4 times itself?
sum becomes double in 14 years. In how many years will it become 4 times itself?
a)
58 years
58 years
b)
42 years
42 years
c)
28 years
28 years
d)
56 years
56 years
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8).A sum of money becomes Rs. 2500 in 2 years
and Rs. 5184 in 4 years on compound interest. Find the rate of compound
interest.
and Rs. 5184 in 4 years on compound interest. Find the rate of compound
interest.
a)
44%
44%
b)
50%
50%
c)
40%
40%
d)
36%
36%
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9).In a military camp, ration was stored for
660 militants at the rate of 800 gramps per militant for 45 days. After 10 days
some more militants came from other camp and the remaining ration got finished
only in 15 days at the rate of 1400 gramps per militant. Find the number of
militants coming in.
660 militants at the rate of 800 gramps per militant for 45 days. After 10 days
some more militants came from other camp and the remaining ration got finished
only in 15 days at the rate of 1400 gramps per militant. Find the number of
militants coming in.
a)
240
240
b)
248
248
c)
240
240
d)
220
220
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10).16 men or 20 boys can do a piece of work
in 30 days. The number of days that 15 men and 15 boys would take to finish the
same work is
in 30 days. The number of days that 15 men and 15 boys would take to finish the
same work is
a)
13×7/9
13×7/9
b)
17×1/7
17×1/7
c)
15×5/9
15×5/9
d)
17×7/9
17×7/9
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Check here below for the detailed
solution of the above aptitude questions:
solution of the above aptitude questions:
1.)
Given series 16, 32, 48, 64 ….
Given series 16, 32, 48, 64 ….
Common
difference (d) = 32 – 16 = 16
difference (d) = 32 – 16 = 16
First
term = (a) = 16
term = (a) = 16
30th
term = t30 = a + (n – 1) d
term = t30 = a + (n – 1) d
=
16 + (30 – 1) 16
16 + (30 – 1) 16
=
16 + 29 × 16 = 480
16 + 29 × 16 = 480
Now,
34th term = t34= a + (n-1) d
34th term = t34= a + (n-1) d
=
16 + (34 – 1) 16
16 + (34 – 1) 16
=
16 + 33 × 16 = 544
16 + 33 × 16 = 544
Required
difference = 544 – 480 = 64
difference = 544 – 480 = 64
Answer: d
2).
Let the HCF be x.
Let the HCF be x.
So,
LCM =55x
LCM =55x
According
to the question,
to the question,
55x
+ x = 6272
+ x = 6272
Or,
56x = 6272
56x = 6272
X
= 112
= 112
Now,
LCM × HCF = First number × Second number
LCM × HCF = First number × Second number
Or,
55x × x = 280 × second number
55x × x = 280 × second number
Or,
55 × 112 × 112 = 280 × second number
55 × 112 × 112 = 280 × second number
Second
number = (55×112×112)/280
number = (55×112×112)/280
=
2464
2464
Answer: a
3).
Saving percentages of A, B and C are 30%, 25% and 20% respectively.
Saving percentages of A, B and C are 30%, 25% and 20% respectively.
Now,
(A×30)/100: (B×25)/100: (C×20)/100 = 4: 5: 6
(A×30)/100: (B×25)/100: (C×20)/100 = 4: 5: 6
Or,
3A/10: B/4: C/5 = 4: 5: 6
3A/10: B/4: C/5 = 4: 5: 6
Or,
6A: 5B: 4C = 4/6: 5/5: 6/4
6A: 5B: 4C = 4/6: 5/5: 6/4
A:
B: C = 2/3:1:3/2
B: C = 2/3:1:3/2
Multiplying
each ration by 6,
each ration by 6,
A:
B: C = 4:6:9
B: C = 4:6:9
Now
the sum of the ratios = 4 + 6 + 9 = 19
the sum of the ratios = 4 + 6 + 9 = 19
Earning
of B = (6/19) × 95000 = Rs. 30000
of B = (6/19) × 95000 = Rs. 30000
Earning
of C = (9/19) × 95000 = Rs. 45000
of C = (9/19) × 95000 = Rs. 45000
Required
difference = (45000 – 30000)
difference = (45000 – 30000)
=
Rs. 15000
Rs. 15000
Answer: d
4).
Let the total number of boys and girls are 100.
Let the total number of boys and girls are 100.
Now,
number of adult boy and girls students
number of adult boy and girls students
=
[(4/5) × 100 × (1/2) + (1/5) × (3/4) × 100)] = 40 + 15 = 55
[(4/5) × 100 × (1/2) + (1/5) × (3/4) × 100)] = 40 + 15 = 55
Number
of non – adult students
of non – adult students
=
(100 – 55) = 45
(100 – 55) = 45
Required
percentage = 45%
percentage = 45%
Answer: b
5).
Let the cost price be Rs. 100
Let the cost price be Rs. 100
SP
at 20% profit = Rs. 120
at 20% profit = Rs. 120
CP
on 10% more = Rs. 110
on 10% more = Rs. 110
SP
on 25% profit = (110 × 125)/100 = Rs. 137.5
on 25% profit = (110 × 125)/100 = Rs. 137.5
Difference
of selling price = (137.5 – 120) = Rs. 17.5
of selling price = (137.5 – 120) = Rs. 17.5
On
Rs. 17.5 more the CP is Rs. 100
Rs. 17.5 more the CP is Rs. 100
On
Rs. 70 more the CP is (100/17.5×70)
Rs. 70 more the CP is (100/17.5×70)
=
(100×10×70)/175 = Rs. 400
(100×10×70)/175 = Rs. 400
Answer: c
6).
SP at 40% discount = (1000×60)/100 = Rs. 600
SP at 40% discount = (1000×60)/100 = Rs. 600
SP
at 36% and 5% successive discounts
at 36% and 5% successive discounts
=
1000 × (64/100) × (95/100) = Rs. 608
1000 × (64/100) × (95/100) = Rs. 608
Required
difference = (608 – 600) = Rs. 8
difference = (608 – 600) = Rs. 8
Answer: a
7).
Let the principal be Rs. 100
Let the principal be Rs. 100
Time
= 14 years
= 14 years
Amount
= Rs. 200
= Rs. 200
Interest
= (200 – 100) = Rs. 100
= (200 – 100) = Rs. 100
Rate
= [(Interest × 100)/(Principal × time)] = [(100×100)/(100×14)] %
= [(Interest × 100)/(Principal × time)] = [(100×100)/(100×14)] %
=
50/7%
50/7%
Now,
amount = Rs. 400
amount = Rs. 400
Interest
= (400 – 100) = Rs. 300
= (400 – 100) = Rs. 300
Time
= (Interest × 100/Principal × Rate) = (300 × 100/100 × 50) × 7
= (Interest × 100/Principal × Rate) = (300 × 100/100 × 50) × 7
=
42 years
42 years
Answer: b
8). If a sum of money on compound interest becomes
Rs. x in t1 years and Rs. y in t2 years, (1 + r/100)t2-t1
= y/x
Rs. x in t1 years and Rs. y in t2 years, (1 + r/100)t2-t1
= y/x
Hence,
y = Rs. 5184
y = Rs. 5184
X
= Rs. 2500
= Rs. 2500
t2
= 4 years
= 4 years
t1
= 2 years
= 2 years
So, (1 + r/100)4-2= 5184/2500
Or,
(1+ r/100)2 = 1296/625
(1+ r/100)2 = 1296/625
Or,
1 + r/100 = 36/25
1 + r/100 = 36/25
Or,
r/100 = (36/25) – 1
r/100 = (36/25) – 1
Or,
r = (11/25) × 100
r = (11/25) × 100
r
= 44%
= 44%
Answer: a
9).
Remaining time = (45 – 10)
Remaining time = (45 – 10)
=
35 days
35 days
Present
militants = 660
militants = 660
Let
the number of militants coming in be x
the number of militants coming in be x
Total
militants = (660 + x)
militants = (660 + x)
If
x militants had not come, 660 militants would have eaten the remaining ration
at the rate of 800 grams per militant in 35 days ….. (i)
x militants had not come, 660 militants would have eaten the remaining ration
at the rate of 800 grams per militant in 35 days ….. (i)
Now,
(660 + x) militants are the remaining ration at the rate of 1400 gram/militant
in 15 days.
(660 + x) militants are the remaining ration at the rate of 1400 gram/militant
in 15 days.
Then,
660 × 800 × 35 = (660 + x) × 1400 × 15
660 × 800 × 35 = (660 + x) × 1400 × 15
Or,
(660 + x) = (660×800×35)/(1400×15)
(660 + x) = (660×800×35)/(1400×15)
Or,
660 + x = 880
660 + x = 880
Or,
x = 880 – 660
x = 880 – 660
X
= 220
= 220
Answer: d
10).
16 men = 20 boys
16 men = 20 boys
1
man = 20/16 = 5/4 boys
man = 20/16 = 5/4 boys
15
men = 75/4 boys
men = 75/4 boys
Total
number of boys = (75/4) + 15 = (75 + 60)/4
number of boys = (75/4) + 15 = (75 + 60)/4
=
135/4 boys
135/4 boys
20
boys can do a piece of work in 30 days.
boys can do a piece of work in 30 days.
1
boy can do a piece of work in 30 × 20 days.
boy can do a piece of work in 30 × 20 days.
135/4
boys can do a piece of work in (30 × 20 × 4)/135 days = 17 × (7/9) days
boys can do a piece of work in (30 × 20 × 4)/135 days = 17 × (7/9) days
Answer: d
